East West Emerald Cut Ring Cz | Solved: C No 35 Question 3 Not Yet Answered Which Of The Following Could Be The Equation Of The Function Graphed Below? Marked Out Of 1 Flag Question Select One =A Asinx + 2 =A 2Sinx+4 Y = 4Sinx+ 2 Y =2Sinx+4 Clear My Choice

Wednesday, 31 July 2024
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This behavior is true for all odd-degree polynomials. Try Numerade free for 7 days. Step-by-step explanation: We are given four different functions of the variable 'x' and a graph. Now let's look at some polynomials of odd degree (cubics in the first row of pictures, and quintics in the second row): As you can see above, odd-degree polynomials have ends that head off in opposite directions. Recall from Chapter 9, Lesson 3, that when the graph of y = g(x) is shifted to the left by k units, the equation of the new function is y = g(x + k). Which of the following could be the equation of the function graphed below? The figure clearly shows that the function y = f(x) is similar in shape to the function y = g(x), but is shifted to the left by some positive distance. The attached figure will show the graph for this function, which is exactly same as given. Which of the following could be the function graphed using. If you can remember the behavior for quadratics (that is, for parabolas), then you'll know the end-behavior for every even-degree polynomial. The only equation that has this form is (B) f(x) = g(x + 2). The actual value of the negative coefficient, −3 in this case, is actually irrelevant for this problem. Ask a live tutor for help now.

Which Of The Following Could Be The Function Graphed Using

Graph D shows both ends passing through the top of the graphing box, just like a positive quadratic would. This function is an odd-degree polynomial, so the ends go off in opposite directions, just like every cubic I've ever graphed. Solved by verified expert. Answer: The answer is. These traits will be true for every even-degree polynomial. Question 3 Not yet answered. Create an account to get free access. We solved the question! Check the full answer on App Gauthmath. Which of the following could be the function graphed following. Clearly Graphs A and C represent odd-degree polynomials, since their two ends head off in opposite directions.

Which Of The Following Could Be The Function Graphed Is F

Since the sign on the leading coefficient is negative, the graph will be down on both ends. Gauth Tutor Solution. Crop a question and search for answer. One of the aspects of this is "end behavior", and it's pretty easy.

Which Of The Following Could Be The Function Graphed Following

Provide step-by-step explanations. Matches exactly with the graph given in the question. Unlimited access to all gallery answers. We see that the graph of first three functions do not match with the given graph, but the graph of the fourth function given by. Which of the following could be the function graph - Gauthmath. The exponent says that this is a degree-4 polynomial; 4 is even, so the graph will behave roughly like a quadratic; namely, its graph will either be up on both ends or else be down on both ends. First, let's look at some polynomials of even degree (specifically, quadratics in the first row of pictures, and quartics in the second row) with positive and negative leading coefficients: Content Continues Below.

Which Of The Following Could Be The Function Graphed Without

When the graphs were of functions with negative leading coefficients, the ends came in and left out the bottom of the picture, just like every negative quadratic you've ever graphed. ← swipe to view full table →. The figure above shows the graphs of functions f and g in the xy-plane. Y = 4sinx+ 2 y =2sinx+4. We'll look at some graphs, to find similarities and differences.

Get 5 free video unlocks on our app with code GOMOBILE. High accurate tutors, shorter answering time. To answer this question, the important things for me to consider are the sign and the degree of the leading term. Answered step-by-step.

But If they start "up" and go "down", they're negative polynomials. Unlimited answer cards. All I need is the "minus" part of the leading coefficient. 12 Free tickets every month. This problem has been solved!